0=2x^2+16

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Solution for 0=2x^2+16 equation: 



0=2x^2+16

We move all terms to the left:

0-(2x^2+16)=0

We add all the numbers together, and all the variables

-(2x^2+16)=0

We get rid of parentheses

-2x^2-16=0

a = -2; b = 0; c = -16;
Δ = b2-4ac
Δ = 02-4·(-2)·(-16)
Δ = -128
Delta is less than zero, so there is no solution for the equation

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